ICCF



AUT Thomas Steinbacher (2354)
   

          
          
          
          
          
          
          
          
 
1.d4 d5 2.c4 dxc4 3.e4 e5 4.Nf3 exd4 5.Bxc4 Nc6 6.O-O Be6 7.Bb5 Bc5 8.b4 Bb6 9.a4 a6 10.Bxc6+ bxc6 11.a5 Ba7 12.Bb2 Nf6 13.Nbd2 O-O 14.Qc2 Nh5 15.g3 Qd6 16.Rfc1 Rfb8 17.Rab1 Ba2 18.Ra1 Be6 19.Rab1 Ba2 20.Ra1 Be6 21.Rab1 Ba2
1/2-1/2

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USA CCE Ferdinand Burmeister (2354)
 

     

 


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