ICCF



SWE Roland Lindahl (1687)
   

          
          
          
          
          
          
          
          
 
1.e4 e6 2.d4 d5 3.Nc3 dxe4 4.Nxe4 Nd7 5.Nf3 Ngf6 6.Nxf6+ Nxf6 7.Bd3 c5 8.O-O cxd4 9.Nxd4 Be7 10.Be3 O-O 11.h3 a6 12.Re1 Re8 13.Nf3 Bd7 14.a3 Qc7 15.Bd4 Bc6 16.Ne5 Rad8 17.c3 b5 18.Nxc6 Qxc6
1/2-1/2

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POL Edmund Belter (1720)
 

     

 


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