ICCF



POL Bogdan Babecki (2128)
   

          
          
          
          
          
          
          
          
 
1.e4 e5 2.Nf3 Nc6 3.Bb5 Nf6 4.O-O Nxe4 5.d4 Nd6 6.Bxc6 dxc6 7.dxe5 Nf5 8.Qxd8+ Kxd8 9.Nc3 Bd7 10.Rd1 Kc8 11.Ng5 Be8 12.b3 b6 13.Bb2 Be7 14.Nge4 a5 15.Rd3 Bd7 16.a4 Be6 17.Ne2 g5 18.Nd6+ Bxd6
1/2-1/2

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BRA CCE Alberto Francisco Dillenburg (2248)
 

     

 


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